What is the general solution for sin(θ)=(sqrt(21))/5 ?

The general solution for sin(θ)=(sqrt(21))/5 is θ=1.15927…+2pin,θ=pi-1.15927…+2pin

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sin(θ)=(sqrt(21))/5

sin (θ) = \frac{21}{5}

θ = 1.15927 \dots + 2 πn, θ = π - 1.15927 \dots + 2 πn

Degrees

θ = 66.42182 \dots^{\circ} + 36 0^{\circ} n, θ = 113.57817 \dots^{\circ} + 36 0^{\circ} n

Solution steps

sin (θ) = \frac{21}{5}

Apply trig inverse properties

sin (θ) = \frac{21}{5}

General solutions for

sin (θ) = \frac{21}{5}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

θ = arcsin (\frac{21}{5}) + 2 πn, θ = π - arcsin (\frac{21}{5}) + 2 πn

θ = arcsin (\frac{21}{5}) + 2 πn, θ = π - arcsin (\frac{21}{5}) + 2 πn

Show solutions in decimal form

θ = 1.15927 \dots + 2 πn, θ = π - 1.15927 \dots + 2 πn

sin (α) = \frac{3}{5}

x, tan^{2} (x) = 1

x, tan^{2} (x) = 2

x, \frac{p}{q} = sin^{2} (x)

cos (2 x) = 1 - 2 (\frac{3}{5})^{2}

What is the general solution for sin(θ)=(sqrt(21))/5 ?
The general solution for sin(θ)=(sqrt(21))/5 is θ=1.15927…+2pin,θ=pi-1.15927…+2pin