What is the general solution for cos(x)= 11/14 ,sin(x) ?

The general solution for cos(x)= 11/14 ,sin(x) is No Solution for x\in\mathbb{R}

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cos(x)= 11/14 ,sin(x)

cos (x) = \frac{11}{14}, sin (x)

No Solution for x \in R

Solution steps

cos (x) = \frac{11}{14}, sin (x)

Apply trig inverse properties

cos (x) = \frac{11}{14}

General solutions for

cos (x) = \frac{11}{14}

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (\frac{11}{14}) + 2 πn, x = 2 π - arccos (\frac{11}{14}) + 2 πn

x = arccos (\frac{11}{14}) + 2 πn, x = 2 π - arccos (\frac{11}{14}) + 2 πn

Solutions for the range

sin (x)

No Solution for x \in R

sin^{2} (2 x) + cos^{2} (3 x) = 1

sin (θ) = 0.9848

cot^{(2)} (x) + 2 cot (x) + 1 = 0

cos (x) cos (x) = \frac{( 1 - sin ^{2} ( x ) )}{sin ( x )}

r^{2} = a^{2} (sin (x) + cos (x))

What is the general solution for cos(x)= 11/14 ,sin(x) ?
The general solution for cos(x)= 11/14 ,sin(x) is No Solution for x\in\mathbb{R}