What is the general solution for arccos(x)=(79)/(9sqrt(70)) ?

The general solution for arccos(x)=(79)/(9sqrt(70)) is x=cos((79sqrt(70))/(630))

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arccos(x)=(79)/(9sqrt(70))

arccos (x) = \frac{79}{9 70}

x = cos (\frac{79 70}{630})

Solution steps

arccos (x) = \frac{79}{9 70}

Simplify

\frac{79}{9 70} : \frac{79 70}{630}

\frac{79}{9 70}

Multiply by the conjugate

\frac{70}{70}

= \frac{79 70}{9 70 70}

97070 = 630

97070

Apply radical rule:

a a = a

7070 = 70

= 9 \cdot 70

Multiply the numbers:

9 \cdot 70 = 630

= 630

= \frac{79 70}{630}

arccos (x) = \frac{79 70}{630}

Apply trig inverse properties

arccos (x) = \frac{79 70}{630}

arccos (x) = a \Rightarrow x = cos (a)

x = cos (\frac{79 70}{630})

x = cos (\frac{79 70}{630})

sin (2 x) sin (x) - cos (2 x) cos (x) = \frac{2}{2}

50 sec^{2} (5 x) tan (5 x) = 25 + tan^{2} (5 x)

cot (x) = 8

tan (θ) = \frac{- 1}{6}

sin (3 v) = sin (1 8^{\circ})

What is the general solution for arccos(x)=(79)/(9sqrt(70)) ?
The general solution for arccos(x)=(79)/(9sqrt(70)) is x=cos((79sqrt(70))/(630))