What is the general solution for 3cos(x)-2=1 ?

The general solution for 3cos(x)-2=1 is x=2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3cos(x)-2=1

3 cos (x) - 2 = 1

x = 2 πn

Degrees

x = 0^{\circ} + 36 0^{\circ} n

Solution steps

3 cos (x) - 2 = 1

Move

2

to the right side

3 cos (x) - 2 = 1

Add

2

to both sides

3 cos (x) - 2 + 2 = 1 + 2

Simplify

3 cos (x) = 3

3 cos (x) = 3

Divide both sides by

3

3 cos (x) = 3

Divide both sides by

3

\frac{3 cos ( x )}{3} = \frac{3}{3}

Simplify

cos (x) = 1

cos (x) = 1

General solutions for

cos (x) = 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = 0 + 2 πn

x = 0 + 2 πn

Solve

x = 0 + 2 πn : x = 2 πn

x = 0 + 2 πn

0 + 2 πn = 2 πn

x = 2 πn

x = 2 πn

sin (4 x) = - sin (2 x)

t, x = 1 - 2 cos (2 t)

x, sin (3 x) = - \frac{3}{2}

cos (x) = 0.587

\frac{sec ( x ) + csc ( x )}{1 + tan ( x )} = sin (x)

What is the general solution for 3cos(x)-2=1 ?
The general solution for 3cos(x)-2=1 is x=2pin