What is the general solution for cot(θ)= 9/40 ?

The general solution for cot(θ)= 9/40 is θ=1.34948…+pin

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cot(θ)= 9/40

cot (θ) = \frac{9}{40}

θ = 1.34948 \dots + πn

Degrees

θ = 77.31961 \dots^{\circ} + 18 0^{\circ} n

Solution steps

cot (θ) = \frac{9}{40}

Apply trig inverse properties

cot (θ) = \frac{9}{40}

General solutions for

cot (θ) = \frac{9}{40}

cot (x) = a \Rightarrow x = arccot (a) + πn

θ = arccot (\frac{9}{40}) + πn

θ = arccot (\frac{9}{40}) + πn

Show solutions in decimal form

θ = 1.34948 \dots + πn

sin (a) = - \frac{1}{2}

5 cos (x) - 2 sin (x) = 0.5

sin (x) = \frac{6}{15}

cot (θ) = 1.4

tan (x) = 0, x

What is the general solution for cot(θ)= 9/40 ?
The general solution for cot(θ)= 9/40 is θ=1.34948…+pin