What is the general solution for tan^2(4x)=0 ?

The general solution for tan^2(4x)=0 is x=(pin)/4

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tan^2(4x)=0

tan^{2} (4 x) = 0

x = \frac{πn}{4}

Degrees

x = 0^{\circ} + 4 5^{\circ} n

Solution steps

tan^{2} (4 x) = 0

Apply rule

x^{n} = 0 \Rightarrow x = 0

tan (4 x) = 0

General solutions for

tan (4 x) = 0

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

4 x = 0 + πn

4 x = 0 + πn

Solve

4 x = 0 + πn : x = \frac{πn}{4}

4 x = 0 + πn

0 + πn = πn

4 x = πn

Divide both sides by

4

4 x = πn

Divide both sides by

4

\frac{4 x}{4} = \frac{πn}{4}

Simplify

x = \frac{πn}{4}

x = \frac{πn}{4}

x = \frac{πn}{4}

cos (\frac{x}{2}) = - 0.4

tan (x - 4 5^{\circ}) - tan (x + 4 5^{\circ}) = 4

sin (x) (2 sin^{2} (x) - 1) = 0

sin (2 x) = 10 cos (x)

- 2 cos (3 θ) = 1, 0 \leq θ \leq 2 π

What is the general solution for tan^2(4x)=0 ?
The general solution for tan^2(4x)=0 is x=(pin)/4