What is the general solution for solvefor x,cos(x)=(sqrt(3))/2 ?

The general solution for solvefor x,cos(x)=(sqrt(3))/2 is x= pi/6+2pin,x=(11pi)/6+2pin

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solvefor x,cos(x)=(sqrt(3))/2

solve for

x, cos (x) = \frac{3}{2}

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Degrees

x = 3 0^{\circ} + 36 0^{\circ} n, x = 33 0^{\circ} + 36 0^{\circ} n

Solution steps

cos (x) = \frac{3}{2}

General solutions for

cos (x) = \frac{3}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

x = \frac{π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

cos (θ) = - \frac{3}{2}, 0 \leq θ \leq 2 π

cos (2 t) = \frac{3}{2}

cos (x) = - 0.3178, 0 \leq x \leq 2 π

arccos (x) = \frac{π}{3}

arccos (x) = \frac{π}{2}

What is the general solution for solvefor x,cos(x)=(sqrt(3))/2 ?
The general solution for solvefor x,cos(x)=(sqrt(3))/2 is x= pi/6+2pin,x=(11pi)/6+2pin