What is the general solution for 10cos(x)=0 ?

The general solution for 10cos(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin

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10cos(x)=0

10 cos (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Degrees

x = 9 0^{\circ} + 36 0^{\circ} n, x = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

10 cos (x) = 0

Divide both sides by

10

10 cos (x) = 0

Divide both sides by

10

\frac{10 cos ( x )}{10} = \frac{0}{10}

Simplify

cos (x) = 0

cos (x) = 0

General solutions for

cos (x) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

3 sin (x) - 2 = - 2

2 sin (x) cos^{2} (x) = - \frac{3}{2} cos (x)

4 sin (x^{\circ}) + 1 = - 2

(2 cos (x) + 1) (3 tan (x) - 1) = 0

α, cos^{2} (α) + cos^{2} (β) = 1

What is the general solution for 10cos(x)=0 ?
The general solution for 10cos(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin