What is the general solution for 2+cos(θ)=0 ?

The general solution for 2+cos(θ)=0 is No Solution for θ\in\mathbb{R}

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2+cos(θ)=0

2 + cos (θ) = 0

No Solution for θ \in R

Solution steps

2 + cos (θ) = 0

Move

2

to the right side

2 + cos (θ) = 0

Subtract

2

from both sides

2 + cos (θ) - 2 = 0 - 2

Simplify

cos (θ) = - 2

cos (θ) = - 2

- 1 \leq cos (x) \leq 1

No Solution for θ \in R

\frac{1 + sin ( x )}{sin ( x )} = 1 + cos (x)

cos (3 x) - cos (5 x) = 0

2 = 2 cos (x)

4 cos (x) = 4 cos (2 x)

cos (θ) = 513, 3 π^{2} < θ < 2 π

What is the general solution for 2+cos(θ)=0 ?
The general solution for 2+cos(θ)=0 is No Solution for θ\in\mathbb{R}