What is the value of 2+4sin(90) ?

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2+4sin(90)

2 + 4 sin (9 0^{\circ})

6

Solution steps

2 + 4 sin (9 0^{\circ})

Use the following trivial identity:

sin (9 0^{\circ}) = 1

sin (9 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

= 2 + 4 \cdot 1

Simplify

= 6

cos ((\frac{37}{2})^{\circ})

10 - 864 cos (2 3^{\circ}) + 985

25 \cdot sin (9.031)

\frac{tan ^{2} ( 3 0 ^{\circ} ) sec ( 4 5 ^{\circ} )}{\frac{1}{s i n ^{2} ( 6 0 ^{\circ} )}}

\frac{( 100 ) ^{2} sin ( 2 ) ( 53 )}{10}