What is the value of 370*cos(120) ?

The value of 370*cos(120) is -185

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370*cos(120)

370 \cdot cos (12 0^{\circ})

- 185

Solution steps

370 cos (12 0^{\circ})

Use the following trivial identity:

cos (12 0^{\circ}) = - \frac{1}{2}

cos (12 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= - \frac{1}{2}

= 370 (- \frac{1}{2})

Simplify

370 (- \frac{1}{2}) : - 185

370 (- \frac{1}{2})

Remove parentheses:

(- a) = - a

= - 370 \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{1 \cdot 370}{2}

Multiply the numbers:

1 \cdot 370 = 370

= - \frac{370}{2}

Divide the numbers:

\frac{370}{2} = 185

= - 185

= - 185

arcsin (0.4134066695)

\frac{14 sin ( 3 0 ^{\circ} )}{sin ( 9 0 ^{\circ} )}

arccos (- 0.99275)

sin (2 5^{\circ}) \cdot 4

sin^{2} (\frac{π - 6}{3})