What is the value of (pi/2)/(sin(pi/2)) ?

The value of (pi/2)/(sin(pi/2)) is pi/2

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(pi/2)/(sin(pi/2))

\frac{\frac{π}{2}}{sin ( \frac{π}{2} )}

\frac{π}{2}

Decimal Notation

1.57079 \dots

Solution steps

\frac{\frac{π}{2}}{sin ( \frac{π}{2} )}

Use the following trivial identity:

sin (\frac{π}{2}) = 1

sin (\frac{π}{2})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

= \frac{\frac{π}{2}}{1}

Simplify

= \frac{π}{2}

\frac{6}{2 tan ( \frac{180}{6} )}

\frac{4.9 sin ( 3 5 ^{\circ} )}{sin ( 8 0 ^{\circ} )}

\frac{π sin ( π ) + cos ( π ) - 1}{( π ) ^{2}}

arccos (\frac{29}{36})

- 3 cos (2 (\frac{π}{3})) + 1

What is the value of (pi/2)/(sin(pi/2)) ?
The value of (pi/2)/(sin(pi/2)) is pi/2