What is the value of (sin(120))/2 ?

The value of (sin(120))/2 is (sqrt(3))/4

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(sin(120))/2

\frac{sin ( 12 0 ^{\circ} )}{2}

\frac{3}{4}

Decimal Notation

0.43301 \dots

Solution steps

\frac{sin ( 12 0 ^{\circ} )}{2}

Use the following trivial identity:

sin (12 0^{\circ}) = \frac{3}{2}

sin (12 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= \frac{\frac{3}{2}}{2}

Simplify

\frac{\frac{3}{2}}{2} : \frac{3}{4}

\frac{\frac{3}{2}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3}{2 \cdot 2}

Multiply the numbers:

2 \cdot 2 = 4

= \frac{3}{4}

= \frac{3}{4}

cos (18 0^{\circ}) + tan (18 0^{\circ}) + sin (27 0^{\circ}) + cos (27 0^{\circ})

70 sin (2 0^{\circ})

2 tan (\frac{0.3 π}{2})

csc (\frac{1}{4})

\frac{sin ( 3 0 ^{\circ} )}{sin ( 19. 2 ^{\circ} )}