What is the value of (sin(120))/pi ?

The value of (sin(120))/pi is (sqrt(3))/(2pi)

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(sin(120))/pi

\frac{sin ( 12 0 ^{\circ} )}{π}

\frac{3}{2 π}

Decimal Notation

0.27566 \dots

Solution steps

\frac{sin ( 12 0 ^{\circ} )}{18 0 ^{\circ}}

Use the following trivial identity:

sin (12 0^{\circ}) = \frac{3}{2}

sin (12 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{3}{2}

= \frac{\frac{3}{2}}{18 0 ^{\circ}}

Simplify

\frac{\frac{3}{2}}{18 0 ^{\circ}} : \frac{3}{36 0 ^{\circ}}

\frac{\frac{3}{2}}{18 0 ^{\circ}}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3}{36 0 ^{\circ}}

= \frac{3}{36 0 ^{\circ}}

sin (\frac{- 1 π}{3})

sin (\frac{49 π}{6}) + tan (\frac{41 π}{4})

75 tan (2 5^{\circ})

\frac{1 - cos ( 4 5 ^{\circ} )}{1 + cos ( 4 5 ^{\circ} )}

e^{2} sin (0)

What is the value of (sin(120))/pi ?
The value of (sin(120))/pi is (sqrt(3))/(2pi)