What is the value of cos(pi)+pi ?

The value of cos(pi)+pi is -1+pi

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cos(pi)+pi

cos (π) + π

- 1 + π

Decimal Notation

2.14159 \dots

Solution steps

cos (π) + π

Use the following trivial identity:

cos (π) = (- 1)

cos (π)

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= (- 1)

= - 1 + π

cos (arcsin (\frac{1}{2}) + arccos (\frac{4}{5}))

(cos (\frac{π}{4}) + i sin (\frac{π}{4}))^{3}

309.4 \cdot (\frac{sin ( 42.3 1 ^{\circ} )}{238.99})

arccos (\frac{8}{13})

sin (\frac{13}{2} π)