What is the value of (38400)cos(60) ?

The value of (38400)cos(60) is 19200

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(38400)cos(60)

(38400) cos (6 0^{\circ})

19200

Solution steps

(38400) cos (6 0^{\circ})

= 38400 cos (6 0^{\circ})

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

cos (6 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

= 38400 \cdot \frac{1}{2}

Simplify

38400 \cdot \frac{1}{2} : 19200

38400 \cdot \frac{1}{2}

Convert element to fraction:

38400 = \frac{38400}{1}

= \frac{1}{2} \cdot \frac{38400}{1}

Cross-cancel common factor:

2

= \frac{19200}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 19200

= 19200

arccot ((\frac{3}{5})^{\circ})

arctan (\frac{5}{7.5})

cos (0.625)

4 \cdot sin^{2} (1 8^{\circ}) + 2 \cdot sin (1 8^{\circ})

1.6 (sin (2) + cos (2))