What is the value of (sec(79.36))(sin(79.36))-(tan(79.36)) ?

The value of (sec(79.36))(sin(79.36))-(tan(79.36)) is 0

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(sec(79.36))(sin(79.36))-(tan(79.36))

(sec (79.3 6^{\circ})) (sin (79.3 6^{\circ})) - (tan (79.3 6^{\circ}))

0

Solution steps

(sec (79.3 6^{\circ})) (sin (79.3 6^{\circ})) - (tan (79.3 6^{\circ}))

= sec (79.3 6^{\circ}) sin (79.3 6^{\circ}) - tan (79.3 6^{\circ})

Rewrite using trig identities:

sec (79.3 6^{\circ}) sin (79.3 6^{\circ}) = tan (79.3 6^{\circ})

sec (79.3 6^{\circ}) sin (79.3 6^{\circ})

Express with sin, cos

sec (79.3 6^{\circ}) sin (79.3 6^{\circ})

Use the basic trigonometric identity:

sec (79.3 6^{\circ}) = \frac{1}{cos ( 79.3 6 ^{\circ} )}

= \frac{1}{cos ( 79.3 6 ^{\circ} )} sin (79.3 6^{\circ})

Simplify

\frac{1}{cos ( 79.3 6 ^{\circ} )} sin (79.3 6^{\circ}) : \frac{sin ( 79.3 6 ^{\circ} )}{cos ( 79.3 6 ^{\circ} )}

\frac{1}{cos ( 79.3 6 ^{\circ} )} sin (79.3 6^{\circ})

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 sin ( 79.3 6 ^{\circ} )}{cos ( 79.3 6 ^{\circ} )}

Multiply:

1 \cdot sin (79.3 6^{\circ}) = sin (79.3 6^{\circ})

= \frac{sin ( 79.3 6 ^{\circ} )}{cos ( 79.3 6 ^{\circ} )}

= \frac{sin ( 79.3 6 ^{\circ} )}{cos ( 79.3 6 ^{\circ} )}

= \frac{sin ( 79.3 6 ^{\circ} )}{cos ( 79.3 6 ^{\circ} )}

Use the basic trigonometric identity:

\frac{sin ( 79.3 6 ^{\circ} )}{cos ( 79.3 6 ^{\circ} )} = tan (79.3 6^{\circ})

= tan (79.3 6^{\circ})

= tan (79.3 6^{\circ})

= tan (79.3 6^{\circ}) - tan (79.3 6^{\circ})

Simplify

= 0

60 sin (4 1^{\circ})

sec^{5} (0)

- sin (\frac{π}{6}) - cos (\frac{π}{6} + \frac{π}{6})

\frac{( 7.51 ) ^{2} \cdot sin ( 3 0 ^{\circ} )}{9.4}

- 2 cos (- 1)

What is the value of (sec(79.36))(sin(79.36))-(tan(79.36)) ?
The value of (sec(79.36))(sin(79.36))-(tan(79.36)) is 0