What is the value of -sin(pi(2))pi ?

The value of -sin(pi(2))pi is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-sin(pi(2))pi

- sin (π (2)) π

0

Solution steps

- sin (π (2)) π

= - sin (π 2) π

Rewrite using trig identities:

sin (π 2) = 0

sin (π 2)

sin (π 2) = sin (0)

sin (π 2)

Rewrite

π 2

2 π + 0

= sin (2 π + 0)

Apply the periodicity of

sin

sin (x + 2 π) = sin (x)

sin (2 π + 0) = sin (0)

= sin (0)

= sin (0)

Use the following trivial identity:

sin (0) = 0

sin (0)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= 0

= - 0 π

Simplify

= 0

\frac{1909.86}{tan ( 14. 2 ^{\circ} )}

\frac{sin ( \frac{π}{3} )}{\frac{π}{3}}

cos (arctan (\frac{12}{5})) - (arcsin (- \frac{3}{5}))

sin (22 5^{\circ}) + cos (- 13 5^{\circ})

arccos (\frac{3}{6})