What is the value of sin((2pi)/8) ?

The value of sin((2pi)/8) is (sqrt(2))/2

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sin((2pi)/8)

sin (\frac{2 π}{8})

\frac{2}{2}

Decimal Notation

0.70710 \dots

Solution steps

sin (\frac{2 π}{8})

Simplify:

\frac{2 π}{8} = \frac{π}{4}

\frac{2 π}{8}

Cancel the common factor:

2

= \frac{π}{4}

= sin (\frac{π}{4})

Use the following trivial identity:

sin (\frac{π}{4}) = \frac{2}{2}

sin (\frac{π}{4})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{2}{2}

= \frac{2}{2}

arccsc (- 4)

arccos (- 0.25)

tan (\frac{- 7 π}{6})

cos (\frac{π}{12}) + cos (\frac{5 π}{12})

arctan (2.6)