What is the value of -sin(-30) ?

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-sin(-30)

- sin (- 3 0^{\circ})

\frac{1}{2}

Decimal Notation

0.5

Solution steps

- sin (- 3 0^{\circ})

Rewrite using trig identities:

sin (- 3 0^{\circ}) = - \frac{1}{2}

sin (- 3 0^{\circ})

Use the following property:

sin (- x) = - sin (x)

sin (- 3 0^{\circ}) = - sin (3 0^{\circ})

= - sin (3 0^{\circ})

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

sin (3 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= - \frac{1}{2}

= - (- \frac{1}{2})

Simplify

= \frac{1}{2}

arctan (\frac{10296}{11753})

arcsin (cos (arcsin (\frac{3}{2})))

tan (\frac{π}{7}) \cdot tan (\frac{2 π}{7}) \cdot tan (\frac{3 π}{7})

cos (\frac{π}{12}) + sin (\frac{π}{12})

tan (- 6)