What is the value of 4(cos(45))+10(sec(45)) ?

The value of 4(cos(45))+10(sec(45)) is 12sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4(cos(45))+10(sec(45))

4 (cos (4 5^{\circ})) + 10 (sec (4 5^{\circ}))

122

Decimal Notation

16.97056 \dots

Solution steps

4 (cos (4 5^{\circ})) + 10 (sec (4 5^{\circ}))

= 4 cos (4 5^{\circ}) + 10 sec (4 5^{\circ})

Use the following trivial identity:

cos (4 5^{\circ}) = \frac{2}{2}

cos (4 5^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{2}{2}

Use the following trivial identity:

sec (4 5^{\circ}) = 2

sec (4 5^{\circ})

sec (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

= 2

= 4 \cdot \frac{2}{2} + 102

Simplify

4 \cdot \frac{2}{2} + 102 : 122

4 \cdot \frac{2}{2} + 102

4 \cdot \frac{2}{2} = 22

4 \cdot \frac{2}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 \cdot 4}{2}

Divide the numbers:

\frac{4}{2} = 2

= 22

= 22 + 102

Add similar elements:

22 + 102 = 122

= 122

= 122

2 \cdot 0.48 \cdot sin (3 0^{\circ})

arccos (\frac{0}{80})

cos (311. 8^{\circ})

arcsin (\frac{8}{11})

7 sin (6 5^{\circ})

What is the value of 4(cos(45))+10(sec(45)) ?
The value of 4(cos(45))+10(sec(45)) is 12sqrt(2)