What is the value of 2sin((2pi)/2) ?

The value of 2sin((2pi)/2) is 0

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2sin((2pi)/2)

2 sin (\frac{2 π}{2})

0

Solution steps

2 sin (\frac{2 π}{2})

Rewrite using trig identities:

sin (\frac{2 π}{2}) = 0

sin (\frac{2 π}{2})

Simplify

= sin (π)

Use the following trivial identity:

sin (π) = 0

sin (π)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= 0

= 2 \cdot 0

Simplify

= 0

cos (\frac{29 π}{4})

cot (\frac{3}{5})

cos (4 5^{0}) cos (6 0^{0}) + sin (4 5^{0}) sin (6 0^{0})

cos (15. 2^{\circ})

\frac{1}{2} sech^{2} (1) - \frac{1}{2} tanh (1)