What is the value of 1-sin^2(pi/2) ?

The value of 1-sin^2(pi/2) is 0

Popular >

1-sin^2(pi/2)

1 - sin^{2} (\frac{π}{2})

0

Solution steps

1 - sin^{2} (\frac{π}{2})

Use the following trivial identity:

sin (\frac{π}{2}) = 1

sin (\frac{π}{2})

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

= 1 - 1^{2}

Simplify

= 0

5 sin (\frac{2 π}{3})

500 sec^{2} (arctan (\frac{1}{2})) (12 π)

sin (arccos (\frac{5}{13}))

cos (\frac{5 π}{12}) cos (\frac{π}{4}) + sin (\frac{5 π}{12}) sin (\frac{π}{4})

sec (- \frac{11 π}{6})