What is the value of sin(arccos(-15/17)) ?

The value of sin(arccos(-15/17)) is 8/17

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sin(arccos(-15/17))

sin (arccos (- \frac{15}{17}))

\frac{8}{17}

Decimal Notation

0.47058 \dots

Solution steps

sin (arccos (- \frac{15}{17}))

Rewrite using trig identities:

sin (arccos (- \frac{15}{17})) = 1 - (- \frac{15}{17})^{2}

Use the following identity:

sin (arccos (x)) = 1 - x^{2}

= 1 - (- \frac{15}{17})^{2}

= 1 - (- \frac{15}{17})^{2}

Simplify

= \frac{8}{17}

cos^{2} (6 2^{\circ})

\frac{1}{2} \cdot 5.4 \cdot 16 \cdot sin (6 2^{\circ})

- \frac{1}{2} sec^{2} (\frac{π}{4})

arccos (\frac{0.4}{0.4})

tan (7 8^{\circ}) \cdot 5

What is the value of sin(arccos(-15/17)) ?
The value of sin(arccos(-15/17)) is 8/17