What is the value of (9.4)cos(60) ?

The value of (9.4)cos(60) is 47/10

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(9.4)cos(60)

(9.4) cos (6 0^{\circ})

\frac{47}{10}

Decimal Notation

4.7

Solution steps

(9.4) cos (6 0^{\circ})

= \frac{47}{5} cos (6 0^{\circ})

Use the following trivial identity:

cos (6 0^{\circ}) = \frac{1}{2}

cos (6 0^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{1}{2}

= \frac{47}{5} \cdot \frac{1}{2}

Simplify

\frac{47}{5} \cdot \frac{1}{2} : \frac{47}{10}

\frac{47}{5} \cdot \frac{1}{2}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{47 \cdot 1}{5 \cdot 2}

Multiply the numbers:

47 \cdot 1 = 47

= \frac{47}{5 \cdot 2}

Multiply the numbers:

5 \cdot 2 = 10

= \frac{47}{10}

= \frac{47}{10}

arccos (14)

arctan (\frac{28.98}{48.28})

- 2 cos (\frac{π}{3}) csc (\frac{( \frac{π}{3} )}{2})

\frac{1}{sin ( \frac{- 3 π}{4} )}

tan (\frac{11}{60})