What is the value of 5arcsin(-1) ?

The value of 5arcsin(-1) is -(5pi)/2

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5arcsin(-1)

5 arcsin (- 1)

- \frac{5 π}{2}

Decimal Notation

- 450

Solution steps

5 arcsin (- 1)

Rewrite using trig identities:

arcsin (- 1) = - \frac{π}{2}

arcsin (- 1)

Use the following property:

arcsin (- x) = - arcsin (x)

arcsin (- 1) = - arcsin (1)

= - arcsin (1)

Use the following trivial identity:

arcsin (1) = \frac{π}{2}

arcsin (1)

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= \frac{π}{2}

= - \frac{π}{2}

= 5 (- \frac{π}{2})

Simplify

5 (- \frac{π}{2}) : - \frac{5 π}{2}

5 (- \frac{π}{2})

Remove parentheses:

(- a) = - a

= - 5 \cdot \frac{π}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{π 5}{2}

= - \frac{5 π}{2}

8 (cos (6 0^{\circ}) + i \cdot sin (6 0^{\circ}))

7 cos (5.8 \cdot π)

10 sin (13 5^{\circ})

1 0^{3} ln (10) + sec (1 0^{\circ})

sin (4 0^{\circ}) + sin (2 0^{\circ})