What is the value of (1)(1-20/100+1/(2pi)(sin(2pi)(20/100))) ?

The value of (1)(1-20/100+1/(2pi)(sin(2pi)(20/100))) is 4/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1)(1-20/100+1/(2pi)(sin(2pi)(20/100)))

(1) (1 - \frac{20}{100} + \frac{1}{2 π} (sin (2 π) (\frac{20}{100})))

\frac{4}{5}

Decimal Notation

0.8

Solution steps

(1) (1 - \frac{20}{100} + \frac{1}{2 π} (sin (2 π) (\frac{20}{100})))

= 1 \cdot (1 - \frac{20}{100} + \frac{1}{2 π} sin (2 π) \frac{20}{100})

Rewrite using trig identities:

sin (2 π) = 0

sin (2 π)

sin (2 π) = sin (0)

sin (2 π)

Rewrite

2 π

2 π + 0

= sin (2 π + 0)

Apply the periodicity of

sin

sin (x + 2 π) = sin (x)

sin (2 π + 0) = sin (0)

= sin (0)

= sin (0)

Use the following trivial identity:

sin (0) = 0

sin (0)

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 0

= 0

= 1 \cdot (1 - \frac{20}{100} + \frac{1}{2 π} \cdot 0 \cdot \frac{20}{100})

Simplify

1 \cdot (1 - \frac{20}{100} + \frac{1}{2 π} \cdot 0 \cdot \frac{20}{100}) : \frac{4}{5}

1 \cdot (1 - \frac{20}{100} + \frac{1}{2 π} \cdot 0 \cdot \frac{20}{100})

\frac{20}{100} = \frac{1}{5}

\frac{20}{100}

Cancel the common factor:

20

= \frac{1}{5}

\frac{1}{2 π} \cdot 0 \cdot \frac{20}{100} = 0

\frac{1}{2 π} \cdot 0 \cdot \frac{20}{100}

\frac{20}{100} = \frac{1}{5}

\frac{20}{100}

Cancel the common factor:

20

= \frac{1}{5}

= 0 \cdot \frac{1}{5} \cdot \frac{1}{2 π}

Multiply fractions:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= 0 \cdot \frac{1 \cdot 1}{2 \cdot 5 π}

\frac{1 \cdot 1}{2 π 5} = \frac{1}{10 π}

\frac{1 \cdot 1}{2 π 5}

Multiply the numbers:

1 \cdot 1 = 1

= \frac{1}{2 \cdot 5 π}

Multiply the numbers:

2 \cdot 5 = 10

= \frac{1}{10 π}

= 0 \cdot \frac{1}{10 π}

Apply rule

0 \cdot a = 0

= 0

= 1 \cdot (- \frac{1}{5} + 1 + 0)

Add the numbers:

1 + 0 = 1

= 1 \cdot (- \frac{1}{5} + 1)

Join

- \frac{1}{5} + 1 : \frac{4}{5}

- \frac{1}{5} + 1

Convert element to fraction:

1 = \frac{1 \cdot 5}{5}

= \frac{1 \cdot 5}{5} - \frac{1}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 5 - 1}{5}

1 \cdot 5 - 1 = 4

1 \cdot 5 - 1

Multiply the numbers:

1 \cdot 5 = 5

= 5 - 1

Subtract the numbers:

5 - 1 = 4

= 4

= \frac{4}{5}

= 1 \cdot \frac{4}{5}

Multiply:

1 \cdot \frac{4}{5} = \frac{4}{5}

= \frac{4}{5}

= \frac{4}{5}

csc (3 0^{\circ}) - tan (4 5^{\circ})

sin (2 π - 1 π)

80 \cdot cos (4 0^{\circ})

36 sin (8 0^{\circ})

arctan (\frac{50}{200})

What is the value of (1)(1-20/100+1/(2pi)(sin(2pi)(20/100))) ?
The value of (1)(1-20/100+1/(2pi)(sin(2pi)(20/100))) is 4/5