What is the value of tan^2((5pi)/6) ?

The value of tan^2((5pi)/6) is 1/3

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tan^2((5pi)/6)

tan^{2} (\frac{5 π}{6})

\frac{1}{3}

Decimal Notation

0.33333 \dots

Solution steps

tan^{2} (\frac{5 π}{6})

Rewrite using trig identities:

sec^{2} (\frac{5 π}{6}) - 1

tan^{2} (\frac{5 π}{6})

Use the Pythagorean identity:

tan^{2} (x) + 1 = sec^{2} (x)

tan^{2} (x) = sec^{2} (x) - 1

= sec^{2} (\frac{5 π}{6}) - 1

= sec^{2} (\frac{5 π}{6}) - 1

Use the following trivial identity:

sec (\frac{5 π}{6}) = - \frac{2 3}{3}

sec (\frac{5 π}{6})

sec (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

= - \frac{2 3}{3}

= (- \frac{2 3}{3})^{2} - 1

Simplify

(- \frac{2 3}{3})^{2} - 1 : \frac{1}{3}

(- \frac{2 3}{3})^{2} - 1

(- \frac{2 3}{3})^{2} = \frac{2 ^{2}}{3}

(- \frac{2 3}{3})^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- \frac{2 3}{3})^{2} = (\frac{2 3}{3})^{2}

= (\frac{2 3}{3})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 3 ) ^{2}}{3 ^{2}}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

(23)^{2} = 2^{2} (3)^{2}

= \frac{2 ^{2} ( 3 ) ^{2}}{3 ^{2}}

(3)^{2} : 3

Apply radical rule:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

Cancel the common factor:

2

= 1

= 3

= \frac{2 ^{2} \cdot 3}{3 ^{2}}

Cancel the common factor:

3

= \frac{2 ^{2}}{3}

= \frac{2 ^{2}}{3} - 1

2^{2} = 4

= \frac{4}{3} - 1

Convert element to fraction:

1 = \frac{1 \cdot 3}{3}

= - \frac{1 \cdot 3}{3} + \frac{4}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 3 + 4}{3}

- 1 \cdot 3 + 4 = 1

- 1 \cdot 3 + 4

Multiply the numbers:

1 \cdot 3 = 3

= - 3 + 4

Add/Subtract the numbers:

- 3 + 4 = 1

= 1

= \frac{1}{3}

= \frac{1}{3}

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