What is the value of 10sin(-30) ?

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10sin(-30)

10 sin (- 3 0^{\circ})

- 5

Solution steps

10 sin (- 3 0^{\circ})

Rewrite using trig identities:

sin (- 3 0^{\circ}) = - \frac{1}{2}

sin (- 3 0^{\circ})

Use the following property:

sin (- x) = - sin (x)

sin (- 3 0^{\circ}) = - sin (3 0^{\circ})

= - sin (3 0^{\circ})

Use the following trivial identity:

sin (3 0^{\circ}) = \frac{1}{2}

sin (3 0^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= - \frac{1}{2}

= 10 (- \frac{1}{2})

Simplify

10 (- \frac{1}{2}) : - 5

10 (- \frac{1}{2})

Remove parentheses:

(- a) = - a

= - 10 \cdot \frac{1}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= - \frac{1 \cdot 10}{2}

Multiply the numbers:

1 \cdot 10 = 10

= - \frac{10}{2}

Divide the numbers:

\frac{10}{2} = 5

= - 5

= - 5

\frac{7 2 ^{2} \cdot sin ( 2 \cdot 35 ) \cdot 100 0 ^{2}}{9.8 \cdot 6 0 ^{2} \cdot 6 0 ^{2}}

\frac{π ^{2}}{2} - 2 cos (π)

sin (2 π) - sin (\frac{3 π}{2})

12 sin (\frac{2 π}{3})

e cos (1) - e cos (2)