What is the value of 1-(sin(45))/(cos(45)) ?

The value of 1-(sin(45))/(cos(45)) is 0

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1-(sin(45))/(cos(45))

1 - \frac{sin ( 4 5 ^{\circ} )}{cos ( 4 5 ^{\circ} )}

0

Solution steps

1 - \frac{sin ( 4 5 ^{\circ} )}{cos ( 4 5 ^{\circ} )}

Use the following trivial identity:

sin (4 5^{\circ}) = \frac{2}{2}

sin (4 5^{\circ})

sin (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{2}{2}

Use the following trivial identity:

cos (4 5^{\circ}) = \frac{2}{2}

cos (4 5^{\circ})

cos (x)

periodicity table with

36 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= \frac{2}{2}

= 1 - \frac{\frac{2}{2}}{\frac{2}{2}}

Simplify

= 0

tan^{2} (6 0^{\circ}) - sec^{2} (6 0^{\circ}) + cot (4 5^{\circ})

cos (arctan (2))

sin (\frac{2 π}{3}) - cos (\frac{π}{12}) + tan (\frac{5 π}{4})

sin (5 0^{\circ}) sin (1 0^{\circ}) - 2 cos (4 0^{\circ}) - 2 cos (2 0^{\circ})

3 sin (\frac{π}{3}) - \frac{1}{2} cos^{2} (\frac{π}{3}) - \frac{7}{8}

What is the value of 1-(sin(45))/(cos(45)) ?
The value of 1-(sin(45))/(cos(45)) is 0