What is the value of (arctan^2(1))/2 ?

The value of (arctan^2(1))/2 is (pi^2)/(32)

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(arctan^2(1))/2

\frac{arctan ^{2} ( 1 )}{2}

\frac{π ^{2}}{32}

Decimal Notation

17.67

Solution steps

\frac{arctan ^{2} ( 1 )}{2}

Use the following trivial identity:

arctan (1) = \frac{π}{4}

arctan (1)

x 0 \frac{3}{3} 13 arctan (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} arctan (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ}

= \frac{π}{4}

= \frac{( \frac{π}{4} ) ^{2}}{2}

Simplify

\frac{( \frac{π}{4} ) ^{2}}{2} : \frac{π ^{2}}{32}

\frac{( \frac{π}{4} ) ^{2}}{2}

(\frac{π}{4})^{2} = \frac{π ^{2}}{4 ^{2}}

(\frac{π}{4})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{π ^{2}}{4 ^{2}}

= \frac{\frac{π ^{2}}{4 ^{2}}}{2}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π ^{2}}{4 ^{2} \cdot 2}

4^{2} \cdot 2 = 32

4^{2} \cdot 2

4^{2} = 16

= 16 \cdot 2

Multiply the numbers:

16 \cdot 2 = 32

= 32

= \frac{π ^{2}}{32}

= \frac{π ^{2}}{32}

sin (\frac{7}{12 π}) - cos (\frac{π}{12})

arcsec (1.2)

4 + 3 cos (\frac{π}{6})

sec (- 40 5^{\circ})

arcsin (\frac{6}{12})

What is the value of (arctan^2(1))/2 ?
The value of (arctan^2(1))/2 is (pi^2)/(32)