What is the value of sin(arccos(-3/5)) ?

The value of sin(arccos(-3/5)) is 4/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin(arccos(-3/5))

sin (arccos (- \frac{3}{5}))

\frac{4}{5}

Decimal Notation

0.8

Solution steps

sin (arccos (- \frac{3}{5}))

Rewrite using trig identities:

sin (arccos (- \frac{3}{5})) = 1 - (- \frac{3}{5})^{2}

Use the following identity:

sin (arccos (x)) = 1 - x^{2}

= 1 - (- \frac{3}{5})^{2}

= 1 - (- \frac{3}{5})^{2}

Simplify

= \frac{4}{5}

tan (54 0^{\circ})

arccos (\frac{5}{5})

cos (3.14)

2 sin^{2} (\frac{π}{2})

40 cos (6 0^{\circ})