What is the value of arccos(cos(-(7pi)/6)) ?

The value of arccos(cos(-(7pi)/6)) is (5pi)/6

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arccos(cos(-(7pi)/6))

arccos (cos (- \frac{7 π}{6}))

\frac{5 π}{6}

Decimal Notation

150

Solution steps

arccos (cos (- \frac{7 π}{6}))

Use the inverse trig property:

\frac{5 π}{6}

arccos (cos (- \frac{7 π}{6}))

For

0 \leq x \leq π, a rccos (cos (x)) = x

Rewrite using trig identities:

cos (- \frac{7 π}{6}) = cos (\frac{5 π}{6})

cos (- \frac{7 π}{6})

cos (x + 2 π \cdot k) = cos (x)

= cos (- \frac{7 π}{6} + 1 \cdot 2 π)

= cos (\frac{5 π}{6})

= arccos (cos (\frac{5 π}{6}))

0 \leq \frac{5 π}{6} \leq π

= \frac{5 π}{6}

= \frac{5 π}{6}

sin^{2} (4 0^{\circ}) + cos^{2} (4 0^{\circ})

csc (arctan (- \frac{8}{9}))

sin^{2} (21 0^{\circ})

sin (4 5^{\circ}) cos (4 5^{\circ})

sin (23 0^{\circ})

What is the value of arccos(cos(-(7pi)/6)) ?
The value of arccos(cos(-(7pi)/6)) is (5pi)/6