What is the value of arcsin(-1/2)+arccos(1) ?

The value of arcsin(-1/2)+arccos(1) is -pi/6

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arcsin(-1/2)+arccos(1)

arcsin (- \frac{1}{2}) + arccos (1)

- \frac{π}{6}

Decimal Notation

- 30

Solution steps

arcsin (- \frac{1}{2}) + arccos (1)

Rewrite using trig identities:

arcsin (- \frac{1}{2}) = - \frac{π}{6}

arcsin (- \frac{1}{2})

Use the following property:

arcsin (- x) = - arcsin (x)

arcsin (- \frac{1}{2}) = - arcsin (\frac{1}{2})

= - arcsin (\frac{1}{2})

Use the following trivial identity:

arcsin (\frac{1}{2}) = \frac{π}{6}

arcsin (\frac{1}{2})

x 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arcsin (x) 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} arcsin (x) 0^{\circ} 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ}

= \frac{π}{6}

= - \frac{π}{6}

Use the following trivial identity:

arccos (1) = 0

arccos (1)

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= 0

= - \frac{π}{6} + 0

Simplify

= - \frac{π}{6}

sin^{4} (\frac{π}{2})

arccos (0.1)

csc (\frac{8 π}{3})

cot (\frac{9 π}{4})

tan (arccos (\frac{5}{13}))

What is the value of arcsin(-1/2)+arccos(1) ?
The value of arcsin(-1/2)+arccos(1) is -pi/6