What is the general solution for -4cos(x)=0 ?

The general solution for -4cos(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin

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-4cos(x)=0

- 4 cos (x) = 0

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Degrees

x = 9 0^{\circ} + 36 0^{\circ} n, x = 27 0^{\circ} + 36 0^{\circ} n

Solution steps

- 4 cos (x) = 0

Divide both sides by

- 4

- 4 cos (x) = 0

Divide both sides by

- 4

\frac{- 4 cos ( x )}{- 4} = \frac{0}{- 4}

Simplify

cos (x) = 0

cos (x) = 0

General solutions for

cos (x) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

7 cos^{2} (θ) - 3 = - 2 cos (θ) + 2

\frac{sin ( 2 x )}{2} = sin (x)

sin^{2} (θ) + sin (θ) - 6 = 0

y, x + tan (x y) = 0

- sin (2 θ) = 0

What is the general solution for -4cos(x)=0 ?
The general solution for -4cos(x)=0 is x= pi/2+2pin,x=(3pi)/2+2pin