What is the general solution for solvefor y,z=sin(y) ?

The general solution for solvefor y,z=sin(y) is y=arcsin(z)+2pin,y=pi+arcsin(-z)+2pin

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solvefor y,z=sin(y)

solve for

y, z = sin (y)

y = arcsin (z) + 2 πn, y = π + arcsin (- z) + 2 πn

Solution steps

z = sin (y)

Switch sides

sin (y) = z

Apply trig inverse properties

sin (y) = z

General solutions for

sin (y) = z

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π + arcsin (a) + 2 πn

y = arcsin (z) + 2 πn, y = π + arcsin (- z) + 2 πn

y = arcsin (z) + 2 πn, y = π + arcsin (- z) + 2 πn

2 cos (2 x) - 1 = 1 - 2 sin (2 x)

cot^{2} (θ) + 3 csc (θ) = - 3

3 tan^{2} (α) = 3 tan (α)

cos (4 x) + cos (2 x) = 0

sin (x) = \frac{10}{50}

What is the general solution for solvefor y,z=sin(y) ?
The general solution for solvefor y,z=sin(y) is y=arcsin(z)+2pin,y=pi+arcsin(-z)+2pin