What is the general solution for 5sin(θ)+7=0 ?

The general solution for 5sin(θ)+7=0 is No Solution for θ\in\mathbb{R}

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5sin(θ)+7=0

5 sin (θ) + 7 = 0

No Solution for θ \in R

Solution steps

5 sin (θ) + 7 = 0

Move

7

to the right side

5 sin (θ) + 7 = 0

Subtract

7

from both sides

5 sin (θ) + 7 - 7 = 0 - 7

Simplify

5 sin (θ) = - 7

5 sin (θ) = - 7

Divide both sides by

5

5 sin (θ) = - 7

Divide both sides by

5

\frac{5 sin ( θ )}{5} = \frac{- 7}{5}

Simplify

sin (θ) = - \frac{7}{5}

sin (θ) = - \frac{7}{5}

- 1 \leq sin (x) \leq 1

No Solution for θ \in R

5 sin (x) tan (x) + 4 tan (x) = 0

y, tan (y) = x

2 cos (x) + 5 = 4

cos (x) = - 0.64

y, x = tan (\frac{π}{4} y)

What is the general solution for 5sin(θ)+7=0 ?
The general solution for 5sin(θ)+7=0 is No Solution for θ\in\mathbb{R}