What is the general solution for 2sin(x)+3=2 ?

The general solution for 2sin(x)+3=2 is x=(7pi)/6+2pin,x=(11pi)/6+2pin

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2sin(x)+3=2

2 sin (x) + 3 = 2

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Degrees

x = 21 0^{\circ} + 36 0^{\circ} n, x = 33 0^{\circ} + 36 0^{\circ} n

Solution steps

2 sin (x) + 3 = 2

Move

3

to the right side

2 sin (x) + 3 = 2

Subtract

3

from both sides

2 sin (x) + 3 - 3 = 2 - 3

Simplify

2 sin (x) = - 1

2 sin (x) = - 1

Divide both sides by

2

2 sin (x) = - 1

Divide both sides by

2

\frac{2 sin ( x )}{2} = \frac{- 1}{2}

Simplify

sin (x) = - \frac{1}{2}

sin (x) = - \frac{1}{2}

General solutions for

sin (x) = - \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

\frac{cos ( x )}{sin ( x )} = 0

sin (2 x) + 3 cos (2 x) = 0

7 cos (x) tan (x) - 5 tan (x) = 0

sec^{2} (x) - 6 sec (x) = 0

9 sec^{2} (x) tan (x) = 12 tan (x)

What is the general solution for 2sin(x)+3=2 ?
The general solution for 2sin(x)+3=2 is x=(7pi)/6+2pin,x=(11pi)/6+2pin