What is the general solution for 1-sin(θ)= 1/2 ?

The general solution for 1-sin(θ)= 1/2 is θ= pi/6+2pin,θ=(5pi)/6+2pin

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1-sin(θ)= 1/2

Solution

1 - sin (θ) = \frac{1}{2}

Solution

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

Degrees

θ = 3 0^{\circ} + 36 0^{\circ} n, θ = 15 0^{\circ} + 36 0^{\circ} n

Solution steps

1 - sin (θ) = \frac{1}{2}

Move

1

to the right side

1 - sin (θ) = \frac{1}{2}

Subtract

1

from both sides

1 - sin (θ) - 1 = \frac{1}{2} - 1

Simplify

1 - sin (θ) - 1 = \frac{1}{2} - 1

Simplify

1 - sin (θ) - 1 : - sin (θ)

1 - sin (θ) - 1

Add similar elements:

1 - 1 = 0

= - sin (θ)

Simplify

\frac{1}{2} - 1 : - \frac{1}{2}

\frac{1}{2} - 1

Convert element to fraction:

1 = \frac{1 \cdot 2}{2}

= - \frac{1 \cdot 2}{2} + \frac{1}{2}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 2 + 1}{2}

- 1 \cdot 2 + 1 = - 1

- 1 \cdot 2 + 1

Multiply the numbers:

1 \cdot 2 = 2

= - 2 + 1

Add/Subtract the numbers:

- 2 + 1 = - 1

= - 1

= \frac{- 1}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{2}

- sin (θ) = - \frac{1}{2}

- sin (θ) = - \frac{1}{2}

- sin (θ) = - \frac{1}{2}

Divide both sides by

- 1

- sin (θ) = - \frac{1}{2}

Divide both sides by

- 1

\frac{- sin ( θ )}{- 1} = \frac{- \frac{1}{2}}{- 1}

Simplify

\frac{- sin ( θ )}{- 1} = \frac{- \frac{1}{2}}{- 1}

Simplify

\frac{- sin ( θ )}{- 1} : sin (θ)

\frac{- sin ( θ )}{- 1}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{sin ( θ )}{1}

Apply rule

\frac{a}{1} = a

= sin (θ)

Simplify

\frac{- \frac{1}{2}}{- 1} : \frac{1}{2}

\frac{- \frac{1}{2}}{- 1}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{\frac{1}{2}}{1}

Apply the fraction rule:

\frac{a}{1} = a

= \frac{1}{2}

sin (θ) = \frac{1}{2}

sin (θ) = \frac{1}{2}

sin (θ) = \frac{1}{2}

General solutions for

sin (θ) = \frac{1}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

θ = \frac{π}{6} + 2 πn, θ = \frac{5 π}{6} + 2 πn

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Frequently Asked Questions (FAQ)

What is the general solution for 1-sin(θ)= 1/2 ?
The general solution for 1-sin(θ)= 1/2 is θ= pi/6+2pin,θ=(5pi)/6+2pin