What is the general solution for tan(θ)= 12/5 ,pi<θ<(3pi)/2 ?

The general solution for tan(θ)= 12/5 ,pi<θ<(3pi)/2 is θ=1.17600…+pi

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tan(θ)= 12/5 ,pi<θ<(3pi)/2

tan (θ) = \frac{12}{5}, π < θ < \frac{3 π}{2}

θ = 1.17600 \dots + π

Degrees

θ = 247.38013 \dots^{\circ}

Solution steps

tan (θ) = \frac{12}{5}, π < θ < \frac{3 π}{2}

Apply trig inverse properties

tan (θ) = \frac{12}{5}

General solutions for

tan (θ) = \frac{12}{5}

tan (x) = a \Rightarrow x = arctan (a) + πn

θ = arctan (\frac{12}{5}) + πn

θ = arctan (\frac{12}{5}) + πn

Solutions for the range

π < θ < \frac{3 π}{2}

θ = arctan (\frac{12}{5}) + π

Show solutions in decimal form

θ = 1.17600 \dots + π

3 tan (3 θ) + 1 = 0, 0 \leq θ \leq 2 π

cos (2 x) - 3 sin (x) = 1

- 2 sin (x) - sin (2 x) = 0

- sin (x) + cos (2 x) = 0

sin (2 x) - cos (3 x) = 0

What is the general solution for tan(θ)= 12/5 ,pi<θ<(3pi)/2 ?
The general solution for tan(θ)= 12/5 ,pi<θ<(3pi)/2 is θ=1.17600…+pi