English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,tan(x^2+y^2)=1

Solution

solve for

x, tan (x^{2} + y^{2}) = 1

Solution

x = \frac{π + 4 πn - 4 y ^{2}}{2}, x = - \frac{π + 4 πn - 4 y ^{2}}{2}

Solution steps

tan (x^{2} + y^{2}) = 1

General solutions for

tan (x^{2} + y^{2}) = 1

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x^{2} + y^{2} = \frac{π}{4} + πn

x^{2} + y^{2} = \frac{π}{4} + πn

Solve

x^{2} + y^{2} = \frac{π}{4} + πn : x = \frac{π + 4 πn - 4 y ^{2}}{2}, x = - \frac{π + 4 πn - 4 y ^{2}}{2}

x^{2} + y^{2} = \frac{π}{4} + πn

Move

y^{2}

to the right side

x^{2} + y^{2} = \frac{π}{4} + πn

Subtract

y^{2}

from both sides

x^{2} + y^{2} - y^{2} = \frac{π}{4} + πn - y^{2}

Simplify

x^{2} = \frac{π}{4} + πn - y^{2}

x^{2} = \frac{π}{4} + πn - y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{π}{4} + πn - y^{2}, x = - \frac{π}{4} + πn - y^{2}

Simplify

\frac{π}{4} + πn - y^{2} : \frac{π + 4 πn - 4 y ^{2}}{2}

\frac{π}{4} + πn - y^{2}

Join

\frac{π}{4} + πn - y^{2} : \frac{π + 4 πn - 4 y ^{2}}{4}

\frac{π}{4} + πn - y^{2}

Convert element to fraction:

πn = \frac{πn 4}{4}, y^{2} = \frac{y ^{2} 4}{4}

= \frac{π}{4} + \frac{πn \cdot 4}{4} - \frac{y ^{2} \cdot 4}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π + πn \cdot 4 - y ^{2} \cdot 4}{4}

= \frac{π + πn \cdot 4 - y ^{2} \cdot 4}{4}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{π + 4 πn - 4 y ^{2}}{4}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

= \frac{π + 4 πn - 4 y ^{2}}{2}

Simplify

- \frac{π}{4} + πn - y^{2} : - \frac{π + 4 πn - 4 y ^{2}}{2}

- \frac{π}{4} + πn - y^{2}

Join

\frac{π}{4} + πn - y^{2} : \frac{π + 4 πn - 4 y ^{2}}{4}

\frac{π}{4} + πn - y^{2}

Convert element to fraction:

πn = \frac{πn 4}{4}, y^{2} = \frac{y ^{2} 4}{4}

= \frac{π}{4} + \frac{πn \cdot 4}{4} - \frac{y ^{2} \cdot 4}{4}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π + πn \cdot 4 - y ^{2} \cdot 4}{4}

= - \frac{- 4 y ^{2} + 4 πn + π}{4}

Simplify

\frac{π + πn \cdot 4 - y ^{2} \cdot 4}{4} : \frac{π + 4 πn - 4 y ^{2}}{2}

\frac{π + πn \cdot 4 - y ^{2} \cdot 4}{4}

Apply radical rule:

assuming

a \geq 0, b \geq 0

= \frac{π + 4 πn - 4 y ^{2}}{4}

4 = 2

4

Factor the number:

4 = 2^{2}

= 2^{2}

Apply radical rule:

2^{2} = 2

= 2

= \frac{π + 4 πn - 4 y ^{2}}{2}

= - \frac{- 4 y ^{2} + 4 πn + π}{2}

= - \frac{π + 4 πn - 4 y ^{2}}{2}

x = \frac{π + 4 πn - 4 y ^{2}}{2}, x = - \frac{π + 4 πn - 4 y ^{2}}{2}

x = \frac{π + 4 πn - 4 y ^{2}}{2}, x = - \frac{π + 4 πn - 4 y ^{2}}{2}

Popular Examples

2tan(x)+sec(x)=0

2 tan (x) + sec (x) = 0

2sin(x)cos(x)-7cos(x)=0

2 sin (x) cos (x) - 7 cos (x) = 0

3sin(x)=cos(x)

3 sin (x) = cos (x)

cos(3x)-cos(x)=0

cos (3 x) - cos (x) = 0

7sin(x)cos(x)-10cos(x)=0

7 sin (x) cos (x) - 10 cos (x) = 0