What is the general solution for 2sec(θ)+1=0 ?

The general solution for 2sec(θ)+1=0 is No Solution for θ\in\mathbb{R}

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2sec(θ)+1=0

2 sec (θ) + 1 = 0

No Solution for θ \in R

Solution steps

2 sec (θ) + 1 = 0

Move

1

to the right side

2 sec (θ) + 1 = 0

Subtract

1

from both sides

2 sec (θ) + 1 - 1 = 0 - 1

Simplify

2 sec (θ) = - 1

2 sec (θ) = - 1

Divide both sides by

2

2 sec (θ) = - 1

Divide both sides by

2

\frac{2 sec ( θ )}{2} = \frac{- 1}{2}

Simplify

sec (θ) = - \frac{1}{2}

sec (θ) = - \frac{1}{2}

sec (x) \leq - 1 or sec (x) \geq 1

No Solution for θ \in R

3 arccos (2 x) = 2 π

3 cos (x) = 1

cos (a) = \frac{4}{5}

5 - 10 sin^{2} (x) = 0

sec^{2} (θ) - 2 = 0

What is the general solution for 2sec(θ)+1=0 ?
The general solution for 2sec(θ)+1=0 is No Solution for θ\in\mathbb{R}