What is the general solution for sin(t)=(sqrt(3))/2 ?

The general solution for sin(t)=(sqrt(3))/2 is t= pi/3+2pin,t=(2pi)/3+2pin

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sin(t)=(sqrt(3))/2

sin (t) = \frac{3}{2}

t = \frac{π}{3} + 2 πn, t = \frac{2 π}{3} + 2 πn

Degrees

t = 6 0^{\circ} + 36 0^{\circ} n, t = 12 0^{\circ} + 36 0^{\circ} n

Solution steps

sin (t) = \frac{3}{2}

General solutions for

sin (t) = \frac{3}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

t = \frac{π}{3} + 2 πn, t = \frac{2 π}{3} + 2 πn

t = \frac{π}{3} + 2 πn, t = \frac{2 π}{3} + 2 πn

sin (θ) = \frac{15}{17}

sin (θ) = cos (2 θ)

13 sin (x) + 6 = sin (x)

csc^{4} (x) - 4 csc^{2} (x) = 0

tan^{2} (x) - 2 sec (x) = - 1

What is the general solution for sin(t)=(sqrt(3))/2 ?
The general solution for sin(t)=(sqrt(3))/2 is t= pi/3+2pin,t=(2pi)/3+2pin