What is the general solution for tan(2θ)=0 ?

The general solution for tan(2θ)=0 is θ=(pin)/2

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tan(2θ)=0

tan (2 θ) = 0

θ = \frac{πn}{2}

Degrees

θ = 0^{\circ} + 9 0^{\circ} n

Solution steps

tan (2 θ) = 0

General solutions for

tan (2 θ) = 0

tan (x)

periodicity table with

πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

2 θ = 0 + πn

2 θ = 0 + πn

Solve

2 θ = 0 + πn : θ = \frac{πn}{2}

2 θ = 0 + πn

0 + πn = πn

2 θ = πn

Divide both sides by

2

2 θ = πn

Divide both sides by

2

\frac{2 θ}{2} = \frac{πn}{2}

Simplify

θ = \frac{πn}{2}

θ = \frac{πn}{2}

θ = \frac{πn}{2}

9 tan (x) sin (x) = - 8 sin (x)

sin (\frac{θ}{2}) = - \frac{3}{2}

cos (θ) = 0.98

sec^{2} (x) = 3 tan^{2} (x) - 1

csc (x) + cot (x) = \frac{3}{3}

What is the general solution for tan(2θ)=0 ?
The general solution for tan(2θ)=0 is θ=(pin)/2