What is the general solution for cos(θ)=-5/13 ?

The general solution for cos(θ)=-5/13 is θ=1.96558…+2pin,θ=-1.96558…+2pin

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cos(θ)=-5/13

cos (θ) = - \frac{5}{13}

θ = 1.96558 \dots + 2 πn, θ = - 1.96558 \dots + 2 πn

Degrees

θ = 112.61986 \dots^{\circ} + 36 0^{\circ} n, θ = - 112.61986 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (θ) = - \frac{5}{13}

Apply trig inverse properties

cos (θ) = - \frac{5}{13}

General solutions for

cos (θ) = - \frac{5}{13}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

θ = arccos (- \frac{5}{13}) + 2 πn, θ = - arccos (- \frac{5}{13}) + 2 πn

θ = arccos (- \frac{5}{13}) + 2 πn, θ = - arccos (- \frac{5}{13}) + 2 πn

Show solutions in decimal form

θ = 1.96558 \dots + 2 πn, θ = - 1.96558 \dots + 2 πn

4 sec (θ) + 6 = - 2

- 2 sin (x) + cos (2 x) \cdot 2 = 0

sec^{2} (x) - 2 = tan^{2} (x)

4 tan^{2} (x) - 1 = tan^{2} (x)

tan (θ) sin (θ) + sin (θ) = 0

What is the general solution for cos(θ)=-5/13 ?
The general solution for cos(θ)=-5/13 is θ=1.96558…+2pin,θ=-1.96558…+2pin