What is the value of cot(240) ?

The value of cot(240) is (sqrt(3))/3

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cot(240)

cot (24 0^{\circ})

\frac{3}{3}

Decimal Notation

0.57735 \dots

Solution steps

cot (24 0^{\circ})

cot (24 0^{\circ}) = cot (6 0^{\circ})

cot (24 0^{\circ})

Rewrite

24 0^{\circ}

18 0^{\circ} + 6 0^{\circ}

= cot (18 0^{\circ} + 6 0^{\circ})

Apply the periodicity of

cot

cot (x + 18 0^{\circ}) = cot (x)

cot (18 0^{\circ} + 6 0^{\circ}) = cot (6 0^{\circ})

= cot (6 0^{\circ})

= cot (6 0^{\circ})

Use the following trivial identity:

cot (6 0^{\circ}) = \frac{3}{3}

cot (6 0^{\circ})

cot (x)

periodicity table with

18 0^{\circ} n

cycle:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} cot (x) \mp \infty 31 \frac{3}{3} 0 - \frac{3}{3} - 1 - 3

= \frac{3}{3}

= \frac{3}{3}

arcsin (0.6)

cot (\frac{23 π}{4}) \cdot csc (\frac{4 π}{3})

cos^{2} (9 0^{\circ})

arctan (\frac{2}{2})

arccsc (- 1)