What is (-2+1)^2+5(12/3)-9 ?

The solution to (-2+1)^2+5(12/3)-9 is 12

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(-2+1)^2+5(12/3)-9

(- 2 + 1)^{2} + 5 (\frac{12}{3}) - 9

12

Solution steps

(- 2 + 1)^{2} + 5 (\frac{12}{3}) - 9

\frac{12}{3} = 4

Divide the numbers:

\frac{12}{3} = 4

4

= (- 2 + 1)^{2} + 5 \cdot 4 - 9

Follow the PEMDAS order of operations

Calculate within parentheses

(- 2 + 1) : - 1

- 2 + 1

- 2 + 1 = - 1

= - 1

= (- 1)^{2} + 5 \cdot 4 - 9

Calculate exponents

(- 1)^{2} : 1

(- 1)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{2} = 1^{2} = 1

= 1

= 1 + 5 \cdot 4 - 9

Multiply and divide (left to right)

5 \cdot 4 : 20

5 \cdot 4

5 \cdot 4 = 20

= 20

= 1 + 20 - 9

Add and subtract (left to right)

1 + 20 - 9 : 12

1 + 20 - 9

1 + 20 = 21

= 21 - 9

21 - 9 = 12

= 12

= 12

\frac{15}{25}

10 \cdot 10

2 (1)^{2}

- 6 - 2 (- 3 - 2)

0.15