What is 1+(-2-5)^2+(14-17)*4 ?

The solution to 1+(-2-5)^2+(14-17)*4 is 38

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1+(-2-5)^2+(14-17)*4

1 + (- 2 - 5)^{2} + (14 - 17) \cdot 4

38

Solution steps

1 + (- 2 - 5)^{2} + (14 - 17) \cdot 4

Follow the PEMDAS order of operations

Calculate within parentheses

(- 2 - 5) : - 7

- 2 - 5

- 2 - 5 = - 7

= - 7

= 1 + (- 7)^{2} + (14 - 17) \cdot 4

Calculate within parentheses

(14 - 17) : - 3

14 - 17

14 - 17 = - 3

= - 3

= 1 + (- 7)^{2} - 3 \cdot 4

Calculate exponents

(- 7)^{2} : 49

(- 7)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 7)^{2} = 7^{2} = 49

= 49

= 1 + 49 - 3 \cdot 4

Multiply and divide (left to right)

3 \cdot 4 : 12

3 \cdot 4

3 \cdot 4 = 12

= 12

= 1 + 49 - 12

Add and subtract (left to right)

1 + 49 - 12 : 38

1 + 49 - 12

1 + 49 = 50

= 50 - 12

50 - 12 = 38

= 38

= 38

\frac{8}{2} \cdot (2 \cdot 2)

2^{2} + 2^{3}

- 2^{3} - 3^{2}

\frac{5}{0.5}

(4 - 7)^{2}