What is 12-(2^2-10^2\div 5)+(-6)^2\div 4 ?

The solution to 12-(2^2-10^2\div 5)+(-6)^2\div 4 is 37

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12-(2^2-10^2\div 5)+(-6)^2\div 4

12 - (2^{2} - 1 0^{2} \div 5) + (- 6)^{2} \div 4

37

Solution steps

12 - (2^{2} - 1 0^{2} \div 5) + (- 6)^{2} \div 4

Follow the PEMDAS order of operations

Calculate within parentheses

(2^{2} - 1 0^{2} \div 5) : - 16

2^{2} - 1 0^{2} \div 5

Calculate exponents

2^{2} : 4

2^{2}

2^{2} = 4

= 4

= 4 - 1 0^{2} \div 5

Calculate exponents

1 0^{2} : 100

1 0^{2}

1 0^{2} = 100

= 100

= 4 - 100 \div 5

Multiply and divide (left to right)

100 \div 5 : 20

100 \div 5

100 \div 5 = 20

= 20

= 4 - 20

Add and subtract (left to right)

4 - 20 : - 16

4 - 20

4 - 20 = - 16

= - 16

= - 16

= 12 - (- 16) + (- 6)^{2} \div 4

Calculate exponents

(- 6)^{2} : 36

(- 6)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 6)^{2} = 6^{2} = 36

= 36

= 12 - (- 16) + 36 \div 4

Multiply and divide (left to right)

36 \div 4 : 9

36 \div 4

36 \div 4 = 9

= 9

= 12 - (- 16) + 9

Add and subtract (left to right)

12 - (- 16) + 9 : 37

12 - (- 16) + 9

Apply rule

- (- a) = + a

- (- 16) = + 16

= 12 + 16 + 9

12 + 16 = 28

= 28 + 9

28 + 9 = 37

= 37

= 37

\frac{3}{2} (6) - 3 + \frac{5}{3} (3)

\frac{4 ^{2} - 16}{4 - 4}

\frac{1}{2} (4 \cdot 5) - 2^{3}

2^{0} + 3

\frac{1}{4} (6 + 3 + 1)^{2}

What is 12-(2^2-10^2\div 5)+(-6)^2\div 4 ?
The solution to 12-(2^2-10^2\div 5)+(-6)^2\div 4 is 37