What is (3^2-16)/(3-4) ?

The solution to (3^2-16)/(3-4) is 7

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(3^2-16)/(3-4)

\frac{3 ^{2} - 16}{3 - 4}

7

Solution steps

\frac{3 ^{2} - 16}{3 - 4}

Solve

3^{2} - 16 : - 7

Follow the PEMDAS order of operations

Calculate exponents

3^{2} : 9

3^{2}

3^{2} = 9

= 9

= 9 - 16

Add and subtract (left to right)

9 - 16 : - 7

9 - 16

9 - 16 = - 7

= - 7

= - 7

Solve

3 - 4 : - 1

3 - 4 = - 1

= - 1

= \frac{- 7}{- 1}

Simplify

\frac{- 7}{- 1} : 7

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{7}{1}

Apply rule

\frac{a}{1} = a

= 7

= 7

(6 + 3)^{2}

8 \div 2^{3} - 3 + 5

- 5^{2} - 8 \div 2 \times 4 + 7

\frac{1 0 ^{9} - 1}{999}

5 (- 4 - 2) + 6 (17 - 12)